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5v^2+22v-15=0
a = 5; b = 22; c = -15;
Δ = b2-4ac
Δ = 222-4·5·(-15)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-28}{2*5}=\frac{-50}{10} =-5 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+28}{2*5}=\frac{6}{10} =3/5 $
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